# lesson 1 and 2

 .remove_background_ad { border: 1px solid #555555; padding: .75em; margin: .75em; background-color: #e7e7e7; } .rmbg_image { max-height: 80px; } when can a limit fail to exist? when the limit approaches a different number on both sides how do you evaluate lim (3x^2+4x-5) x-2 plug in 2 where all the x's are what do you do when substitution gives k ___ 0 the limit does not exist what do you do when substitution gives you 0 ___ 0 you have to factor then plug in the limit when the limit goes to infinity, and the degree of the top is smaller than the degree of the bottom then its equal to 0 when the limit is infinity, and the degree of the top is same as the bottom then make a fraction from the leading coefficients when limit is infinity, and the degree of the top is greater than the bottom then divide each term by the highest powerof x in the bottom and simplify state the left & right hand limit state the limit left hand limit is 2right hand limit is 1the limit does not exist b/c they dont go to the same number when they ask to find the continuity then find the domain which means set it equal to 0if its a quotient set the denominator equal to 0 steps to finding continuity at a point see if f(a) is defined meaning when you plug in the point it equals a real # then find the left and right hand limit then see if f(x)=f(a) then its continuous Authorjillmray ID68363 Card Setlesson 1 and 2 Descriptionlimits and one sided limits Updated2011-02-23T11:11:42Z Show Answers