-
DNA Polymerase
a. initially incorporates 1 wrong nucleotide sequence every ~106 bp
b. overall accuracy is much higher at 1 error per 109 bp
-
When an incorrect base pair is recognized, what actions take place?
DNA polymerase reverses its direction by one base pair of DNA.
- The 3’-5’ exonuclease activity of the enzyme allows the incorrect
- base pair to be excised.
Following this excision, the polymerase can re-insert the correct base and replication can continue.
-
DNA replication
- 1. bidirectional and semi-conservative
- 2. Synthesis only in the 5’ to 3’ direction
- 3. requires processive and distributive polymerases
- 4. requires RNA primers on both strands near origin of replication5. highly dependent on Watson-Crick base paring
-
What Proteins and enzymes are used in DNA replication?
RNase H, DNA ligase, DNA polymerase δ, single-stranded DNA binding proteins (SSBs), topoisomerases, helicase, primase, replication protein A (RPA), FEN1
-
DNA replication: Accuracy due to
proofreading of polymerases and DNA repair system
-
DNA Replication on lagging strand
- 1. RNA primer hybridizes to ssDNA (synthesized by primase or RNA polymerase)
- 2. elongation by a DNA polymerase, generating Okazaki fragments
- 3. when the okazaki fragment encounters the next RNA primer, RNase activity (or 5’ to 3’ exonuclease activity by polymerase I in prokaryotes) removes the primer (additional FEN1 in eukaryotes)
- 4. gap filling (by distributive polymerase)
- 5. nick sealing (by DNA ligase
-
Double-stranded DNA is fairly stable and strand separation usually requires high energy.
1. Instead of high temperature, organisms use?
2. They begin at the origin, which tends to be rich in
- 1 Enzymes (ex: DNA helicase, DNA
- Polymerase, RNase, DNA Topoisomerase) in order to bypass this problem.
- 2 AT because they are easier to break
- since they have only two hydrogen bonds whereas GC possesses three hydrogen bonds.
-
Okazaki fragment x2
1. short fragment of DNA created on the lagging strand during DNA replication
2. synthesis is initiated from an RNA primer at the 5’ terminus
-
Polymerase I
DNA repair (gap filling); has 5'->3' activity and both 3'->5' exonuclease(Proofreading) and 5'->3' exonuclease activity (RNA Primer removal)
-
Polymerase II
involved in reparation of damaged DNA; has 3'->5' exonuclease activity
-
Polymerase III
main polymerase in bacteria (elongates in DNA replication); has 3'->5'exonuclease proofreading ability
-
Exonucleases are enzymes that work by?
cleaving nucleotides one at a time from the end of a polynucleotide chain. A hydrolyzing reaction occurs that breaks phosphodiester bonds at either the 3’ or 5’ ends.
-
DNA ligase has applications in both?
DNA repair and replication
-
DNA ligase 2 functions ?
1. links together two DNA strands that have double-strand breaks (a break in both complementary strands of DNA)
2. fixes a single-stranded break where it uses the complementary strand as a template but requires the ligase to create the final phosphodiester bond for full repair.
-
DNA Topoisomerases
1. unwind/wind DNA to control the synthesis of proteins & DNA replication
2. untwist the parental strand of DNA (transesterification).
-
Topoiosomerase I
transient breaks in one strand
-
Topoisomerase II
breaks in both strands
a. essential in bacteria for replication and drug target for antibiotics
b. essential in humans as a target for cancer chemotherapy
-
E. coli & the Polymerases
- 1. DNA polymerase I contains a 5' exonuclease that clips off the RNA primer contained immediately upstream from the site of DNA synthesis in a 5' → 3' manner
- 2. the 5' -> 3' exonuclease activity makes it unsuitable for many applications
- a. can be removed from the holoenzyme to leave a useful molecule (Klenow fragment)
-
Processive vs. Distributive
- 1. processive enzyme: used in the sense of going in a forward direction (5’->3’) and continues down this path without coming unbound, as in DNA Polymerase III.
- Ex: polymerase that carries out many additions of nucleotide b4 dissociating from DNA
- 2. distributive enzyme: catalyzes one cleavage first and then another one on another chain at random (gap filling), as in DNA Polymerase I.
-
Telomere x3
- 1. region of repetitive DNA at the end of a chromosome
- 2. protects the end of the chromosome from deterioration
- 3. “caps” the end of the chromosome, protecting it from homologous recombination and non-homologous end joining.
-
Holliday junction
- a. intermediate in homologous genetic recombination
- b. important in maintaining genomic integrity
- c. exists in prokaryotes and eukaryotes
-
Heteroduplex
- double-stranded (duplex) molecule of nucleic acid originated through the genetic recombination of single complementary strands derived from different sources, such as from different homologous chromosomes
- Ex: Regions where one strand was from one duplex, and the other from the homologous duplex.
-
Transposons
- sequences of DNA that can move around to different positions
- a. process called transposition catalyzed by transposases
- b. two types: simple and replicative transposition
- c. can cause mutations and change the amount of DNA in the genome
- d. insertion sequences possess inverted repeats on both ends
- e. they are flanked by direct repeats (same orientation) in the largest sequence
-
demethylation: methylation of guanine bases is directly reversed by the protein
methyl guanine methyl transferase (MGMT). The reaction is stoichiometric rather than catalytic
-
DNA methylation pattern assists in distinguishing the parental strand from the newly synthesized strand, allowing for?
mismatch repair if a wrong base is incorporated during replication
-
base excision repair
- cellular mechanism that repairs damaged DNA throughout the cell cycle. It is primarily responsible for removing small, non-helix distorting base lesions from the genome.
- i. removal of damaged base by specific glycosidases
- ii. repair of AP sites left after removal of a damaged base (or by spontaneous hydrlysis)
- iii. AP endonucleases/AP lyases excise a basic sugar, gap filling, ligation
-
nucleotide excision repair
- prevent unwanted mutations by removing the vast majority of photodimers
- i. recognize bulky distortions in the shape of the DNA double helix
- ii. endonucleases excise a stretch of nucleotides
- iii. gap-filling in by DNA polymerase I
- iv. ligation by DNA ligase
- v. mismatch: if wrong base is incorporated but is undamaged
- vi. transcription-coupled: lesions block transcription but transcribed regions are repaired faster
-
Both nucleotide excision repair and base excision repair systems require an
endonuclease and a DNA ligase
-
Translesion Synthesis
a. damage tolerance process that allows the DNA replication machinery to replicate past DNA lesions such as thymine dimers or AP sitesb. involves switching out regular DNA polymerases for specialized translesion polymerases (e.g. DNA polymerase V),
-
Recombination Repair
a. daughter strand gap repair
- i. piece of daughter strand replaces damaged portion of parental strand
- ii. normal DNA duplex then repairs daughter strand
- iii. normal DNA duplex replicates missing portion given to daughter strand
- iv. most likely to occur on lagging strand
-
Recombination Repair
b. double-strand break repair
- i. results because of ROS or topoisomerase inhibitors
- ii. can be homologous (yeast) or nonhomologous end joining (mammalian cells)
-
Recombination Repair
c. repair of replication forks
- i. recA binds to ssDNA regions at blocked replication forks to maintain integrity
- ii. fork regression by branch migration (in protected state)
- iii. lesion repair by base or nucleotide expansion repair
- iv. reversal of branch migration
-
Bypass Polymerases
- a. induced upon extensive DNA damage (SOS reponse)
- b. readily dissociates from DNA (distributive process so low processivity)
- c. ensure continued replication if a lesion is encountered by the replication machinery
- d. error prone and lack proofreading ability
- e. induced to prevent a long halt of replication at lesions
-
DNA bases
RNA?
A, T, G, C (in RNA, U replaces T)
-
1. Prokaryotes
- a. 1 polymerase
- b. specific σ factors recognize class of genes
- ex) σ factor binds to RNA polymerase core enzyme
- c. RNA polymerase binds to the promoter region first
-
2. Eukaryotes
a. 3 polymerase
b. transcription factors bind to DNA sequences
c. transcription factors (or TATA binding protein (TBP)) binds to the promoter region first
- d. require transcription factors but not σ factors for transcription
- i. specific transcription factors recognize gene-specific DNA sequences
- ii. transcription factors are proteins that oftentimes form dimers
-
DNA is protected from alkylation (dimethyl sulfate) where enzyme is bound
- i. Pribnow (AT-rich)
- ii. -35 region (conserved and asymmetrical)
-
certain nitrogens usually involved in H-bonding only gets alkylated if ssDNA
i. “open” complex from middle of Pribnow box to around start site (-9 to +2)
ii. easier for AT than GC (Pribnow box now AT-rich)
iii. increase of GC pairs would decrease promoter efficiency
iv. increase of AT pairs would INCREASE promoter efficiency
-
Direction of Transcription
- 1. RNA strand is read from 3’ to 5’
- 2. RNA is synthesized (transcribed) in the 5’ to 3’ direction
-
RNA vs. DNA synthesis
1. RNA polymerase does NOT require a primer
a. RNA polymerase molecules can transcribe one gene simultaneously
2. DNA polymerase DOES require a primer
-
Intercalating chemotherapies
1. Daunomycin and Adriamycin
2. inhibits initiation of RNA transcription
-
Accuracy of RNA Transcription
- 1. doesn’t have to be as accurate as that of DNA
- a. genetic code degenerate (errors may be silent)
- b. quick degradation and re-synthesis (high turnover rate)
- c. one AA substitution in protein is oftentimes without consequence
- 2. no repair system known
- a. degradation and re-synthesis
- b. high turnover rate
-
RNA Processing
1.Coupled Transcription-Translation
for Prokaryotes and Eukaryotes
- 1. Prokaryotes: occurs because prokaryotic mRNA does not need to be transported or processed, therefore, translation can begin immediately after transcription
- 2. Eukaryotes: does not occur because mRNA must be processed and transported before translation can take place
-
RNA Processing
RNA modification for prokaryotes and eukaryotes
1. Prokaryotes: protein translation often occurs with little or no modification
2. Eukaryotes: extensive modification is possible
-
Eukaryotic mRNA
1. 5’-terminal cap (7-methyl G)
2. 3’-terminal poly A tail
3. methylated internal variants
4. splice variants
-
Splicing
- 1. modification of RNA after transcription
- 2. excision of intron sequences (noncoding) and exons are joined
- 3. needed before eukaryotic mRNA can be used for translation
- 4. involves several transesterification processes
- 5. involves the formation of a 2’,5’-phosphodiester bond
- 6. requires Watson-Crick base pairing with other RNA molecules for high accuracy
-
RNA polymerase I
RNA polymerase I carries out the transcription in eukaryotes3. in
prokaryotes, transcription factors are not involved in rRNA transcription
-
small interfering RNAs (siRNAs)
- 1. they have a length of approximately 21-23 nucleotides
- 2. they are double-stranded
- 3. they inhibit gene expression by degrading homologous mRNA
- 4. function (posttranscriptional) gene splicing (degradation of homologous mRNA sequences)
-
What are three functions of salvage pathways?
- Important drug targets for treatment of microbial diseases and/orparasitic diseases. Sites for manipulation of biological systems mutagenesis studies preparation of antibodies
- Biological processes where genetic alterations have severe and far-reaching consequences
-
What is the branch point in purine nucleotide synthesis?
IMP
-
What is a difference between DNA and RNA polymerase with respect to the necessity for primers?
DNA polymerase needs primers while RNA polymerase does not
-
Consequences if DNA synthesis would occur from 3→5
Top: energy for chain elongation would come from hydrolysis of triphosphate of chain
Bottom: removal of a wrong paired 5’-terminal nucleotide triphosphate during proof reading would prevent further chain elongation
-
DNA synthesis on lagging strand requires
RNA fragments as primers (8-10 nt in humans; synthesized by primase or RNA polymerase) for synthesis of Okazaki fragments
-
1. RNA primer removal
2.Gap filling
3. Ligation of nick
- RNase Hybridase
- DNA Polyermase
- DNA Ligase
-
DNA Replication:
Accessory proteins: Sliding clamps
- Task: holding DNA polymerase in contact with DNA
- Allows DNA polymerase to be more processive
- (executes many reactions before dissociating
-
1 DNA polymerase III
2 DNA polymerase I
pol III, main, processive
(pol I, gap filling, distributive) + 3’ → 5’ proofreading exonuclease activity + 5’ → 3’ exonuclease activity (RNase H; primer removal)
-
Topoisomerase in humans and backteria
In bacteria: Topoisomerase II is essential for replication and drug target for antibiotics
In humans: Topoisomerase II is essential: target for cancer chemotherapy
-
origins of replication (ori)
replication bubbles move
Eukaryotes (more DNA!) Thousands of origins (every 3-300 kb, tissue- and species-dependent)
Prokaryotes one single ori
- Termination requires topoisomerase II
- bidirectionaly
-
1.DNA synthesis occurs during
2.Drugs that inhibit DNA replication cause
1. S phase of cell cycle
2. G1- (longest phase of growth) or S cell cycle arrest
-
Recombination
Exchange of genetic info. can be homologous (identical sequence) or non homologous
-
DNA Repair
Q: How to recognize newly synthesized strand (and not "repair" parental strand)?
A: Look at methylation pattern! Higher degree of methylation in parental strand
-
DNA Repair
Bypass polymerases are only induced upon
extensive DNA damage (SOS response) and readily dissociates from DNA (distributive)
-
DNA Repair
Repair of Replication Forks
Stop of replication on continuous strand would be detrimental (controlled by ori)
- Putative mechanism:
- 1. RecA binds to ssDNA regions at blocked replication forks to maintain integrity
- 2. Fork regression by branch migration (in protected state)
- 3. Lesion repair by base or nucleotide excision repair
- 4. Reversal of branch migration
-
RNA Transcription x3
Prokaryotes
Eukaryotes
- 1.Initiation recognition of DNA sequence by RNA polymerase
- 2.Elongation RNA chain synthesis
- 3.Termination release of RNA chain/RNA polymerase from DNA template
Prokaryotes: 1 polymerase + specific σ factors recognize classes of genes
Eukaryotes: 3 polymerases + transcription factors bind to DNA sequences
-
RNA Transcription
How were promoter regions found? Footprinting
1. DNA protected from alkylation (dimethyl sulfate) where enzyme is bound → Pribnow and -35 region
2. Certain nitrogens usually involved in H-bonding only gets alkylated if ssDNA → "open" complex from middle of Pribnow box to ca. start site (-9 to +2)
Easier for A:T than for G:C (Note: Pribnow box is AT rich)
-
RNA polymerase
Doesn not require primer
-
RNA Transcription
Tolerable precision
Tolerable precision
1 wrong base per 104 transcribed bases -genetic code degenerate -one aa substitution in protein often w/out consequences
Genes can be transcribed by several RNA polymerase molecules at the same time
-
Protein Translation =
Ribosomal peptide synthesis from mRNA matrix
-
pont mutation
1.silent
2.nonsence
3.missens
frameshift results from?
1.Amino acid code unchanged
2.Stop codon
3.Change of amino acid code
-insertion/deletion
-
Ribosome have ____ tRNA binding sites
EX)
three tRNA binding sites: A, P, E
-
Protein Translation
4 general steps
1.Initiation
2.Elongation
3.Termination
4.Posttranslational Modification
|
|