math

-ln|cosx|+c

ln|sinx|+c

ln|secx+tanx|+c

-ln|cscx+cotx|+c

integral of (1-cos2x)/2 dx

integral of (1+cos2x)/2 dx

tan(x)-x+c

-x-cot(x)+c

xlnx-x+c

ln|x|+c

1/x

1/(x^2+1)

1/sqrt(1-x^2)

-1/sqrt(1-x^2)

if f(x) is continuous on an open itnerval containing a, then for every x in the interval:

d/dx(integral of [f(t)dt] (a,x))=f(x)

if a function is continuous on [a,b] and F is an anti-deriv of f(x) then

integral of f(x)dx (a,b) = F(b)- F(a)

Avg Val= 1(b-a) * integral f(x)dx (a,b)

integral of f(x)dx (a,b)=(b-a)*f(c)

A=(S^2(rad3))/4

a=.5 (d1*d2)

A=.5h(b1+b2) OR A=hm (m is the midsegment)

A= .5a (apothem)p (perimeter)

A= .5pl + b

(1/3)pir^2h/ pi(r)(l)+(pi)r^2

dy/dt=ky ; k/y

A= Ao e^(kt)

y0 + h times F(x0, y0)

V= integral of pi (f(y))^2 dy (a to b)

V= integral of pi (f(x))^2 dx (a to b)

integral of (f(x) - g(x))^2 dx from to b

integral from a to b of square root of (1+ f'(x)^2) dx