Calculus Physics problem (4 part)

1) Projectile is fired upwards with initial velocity of 96 ft/s from a tower 256 ft high.

How long to reach the max height?
- s(t)= -16t²+96t+256
- v(t)= -32t+96=0
t= 3 seconds
2) Projectile is fired upwards with initial velocity of 96 ft/s from a tower 256 ft high.

What is the maximum height?

s(3)= -16(3)²+96(3)+256

s(3)= 400 ft
3) Projectile is fired upwards with initial velocity of 96 ft/s from a tower 256 ft high.

How long will it take the projectile to reach its starting height on the way down?
- -16t²+96t+256=256
- -16t²+96t=0
- -16t(t-6)=0
- t=0 and t=6
0 or 6 seconds
4) Projectile is fired upwards with initial velocity of 96 ft/s from a tower 256 ft high.

What is the velocity when it passes the starting point on the way down.

-32(6)+96

=-96 ft/s

Author

GoBroncos

ID

357092

Card Set

Calculus Physics problem (4 part)

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Updated

2021-12-07T00:21:12Z