Bio 99 Final Lec 14 (Eukatyotic)

  1. Unconvinced by the RT-PCR results, you perform a qRT-PCR reaction using primers for Gene X and GAPDH again. You get the
    following results. The Ct for GAPDH is the same for both Wt and mutant cells (the value is not important in this case). The Ct for Gene X is 24 for the Wt sample, and is 25 for the mutant sample. What can you conclude based on these results?
    A. Gene X transcription is about 2-fold reduced in the
    mutant compared to Wt
    B. Gene X transcription is slightly reduced in the
    mutant compared to Wt
    C. You cannot conclude anything because you have
    know way to know if each sample had the same amount of total RNA
    A.)
  2. Global gene expression in eukaryotes versus bacteria
    • In bacteria, most genes are expressed (unless specifically repressed).
    • In eukaryotes, most genes are silent until activated.
    • Most repressors turn genes OFF (rather than preventing them from being turned ON)
    • In most cells in multicellular eukaryotes, only about 20% of the genes are expressed (this number is difficult to calculate).
  3. What’s the biggest difference between bacterial and eukaryotic DNA?
    chromatin
  4. General (basal) transcription factors
    • common to most promoters, assemble at promoter, recruit RNA pol (e.g. TFIID, TBP, TAFs, etc.)
    • aka. transcriptional machinery
  5. Transcription activators, DNA-binding activators
    • Bind to other sites (e,g. enhancers), more specific to specific genes, and not as universal as general TFs
    • aka. transcriptional factors
  6. HMG (high mobility group) Proteins
    bends DNA to facilitate looping
  7. HMG is a:



    B. )
  8. Mediator is a



    D. )
  9. Insulators
    Insulators block enhancers from regulating transcription across from the insulator site
  10. Insulator sequences
    about 50 nucleotides, contain a conserved CCCTC sequence
  11. CTCF – CTC-binding factor
    • protein with 11 zinc fingers
    • Binds to insulators
  12. ______ structure is the first barrier to transcription
    Chromatin
  13. Heterochromatin
    region of chromatin associated with gene silencing
  14. Euchromatin
    a more accessible form of chromatin to the transcription machinery. Sensitive to DNaseI digestion.
  15. Chromatin remodeling
    changing chromatin structure to make it more or less accessible
  16. Chromatin remodelling is controlled by at least three mechanisms:
    • 1) Nucleosome repositioning on the DNA
    • 2) Histone variants
    • 3) Histone modification
  17. Nucleosome repositioning on the DNA
    Chromatin remodeling complexes shift the position of nucleosomes so that the promoter is no longer is wrapped around a nucleosome.
  18. Histone variants
    Histone variants can be inserted to substitute for the main histone subunits, altering DNA binding ability
  19. Histone modification
    Histones are modified by acetylation or methylation, altering DNA accessibility.
  20. Acetylation
    • almost always associated with increasing accessibility and activating transcription
    • • Specific lysines on histone tails are acetylated (e.g. H3K9ac)
    • • HATs (histone acetyltransferases) and HDACs (histone deacetylases) regulate histone acetylation
  21. Methylation
    • mostly associated with silencing transcription, but in some cases activation. Usually tri-methylated.
    • Example: H3K9me3
  22. Nucleosome repositioning
    • DNA is wrapped tightly around nucleosomes
    • In order to allow access to those sequences to transcription machinery, the nucleosomes must be shifted
    • SWI/SNF – a chromatin remodeling complex that can reposition nucleosomes to free up the promoter
    • SWI/SNF is recruited to specific regions by transcription activators, thus the transcription activators must bind to their DNA sequences first
  23. How to turn on a gene (7 steps)
    • 1. Transcription factors specific to a gene bind to regulatory sites near or far from the promoter of that gene
    • 2. HATs are recruited to acetylate histone tails
    • 3. Chromatin remodeling complexes (SWI/SNF) are also recruited and reposition the nucleosomes to expose the promoter
    • 4. The chromatin structure around the gene (particularly the promoter) goes from a closed configuration to an open configuration
    • 5. Transcription factors recruit mediator, and architectural regulators bend the DNA into loops, collectively bringing these complexes in close proximity to the promoters
    • 6. All of this begins to recruit the transcription machinery (aka general transcription factors and RNA pol) to assemble on the promoter
    • 7. Transcription initiation occurs
  24. General (basal) transcription factors are:



    C. )
  25. Which term is least associated with positive regulation of transcription?



    C. )
  26. Which factor is least likely to have a positive effect on transcriptional
    activation?



    D. )
  27. Turning off a gene
    • Unlike bacteria (think lac repressor), eukaryotic repressors generally only turn off transcription after it’s already started.
    • Repressors/co-repressors kick off activators and inhibit RNA pol, turning off transcription
    • Histone deacetylation by HDACs leads to a closed chromatin configuration, sealing the closed state
  28. DNA methylation and gene expression
    • Cytosines of CG pairs (also called CpG) can be methylated
    • DNA Methylation at the promoter is almosT always associated with the repression of gene expression and closed chromatin
    • 1) Methylated DNA could inhibit transcriptional machinery from binding to the promoter
    • 2) Methylated DNA could recruit HDACs and other complexes associated with closed chromatin configurations
  29. siRNA
    short interfering RNA. About 21-27 nucleotides long. Sequence is the reverse complement of transcript and will hybridize with it to form double-stranded RNA.
  30. Anti-sense RNA
    an RNA whose sequence is the reverse complement of another RNA (sense RNA). Anti-sense and sense RNA will hybridize to form double-stranded RNA
  31. microRNA (miRNA)
    RNAs produced naturally by cells to regulate gene expression. After processing, they’re around 20-22 nucleotides
  32. The gene whose mRNA is bound to by siRNA becomes ____
    silenced
  33. Who discovered miRNA and what experiment led to the discovery?
    • Craig Mello and Andrew Fire
    • hypothesized that adding RNA that was complementary to an mRNA (i.e. anti-sense RNA) would make the transcript double stranded and block expression. They added anti-sense RNA to mex-3 in nematodes, then measured mex-3 transcripts by staining (the dark color). They also added double stranded RNA (dsRNA) that matched mex-3 as well.
  34. Two ways miRNAs silence genes
    • 1) Perfect or near perfect
    • complementarity
    • • Forms dsRNA structure and the mRNA is rapidly degraded
    • 2) Partial complementarity
    • • RISC complex remains bound to miRNA and mRNA, and translation is physically
    • blocked. Eventually the mRNA is degraded
  35. How do miRNAs recognize their targets?
    • Usually 8mers in the 3’ UTRs of mRNAs (but not always)
    • 1 miRNA can recognize many, many target genes
    • ~5000 human genes are targeted by at least 1 miRNA
    • Each gene can have binding sites for multiple miRNAs
    • miRNAs likely have more subtle regulatory effects on an individual gene, but can impact a lot of genes at once 
    • There are estimated to be around 800 miRNA genes e.g. miR-142, miR-181a
  36. miRNA vs. siRNA
    • miRNA: encoded by the genome
    • siRNA: exagernously added (viruses, researchers)
  37. shRNA
    short-hairpin RNA. Created by researchers. When placed into a DNA plasmid, once transcribed will form a short-hairpin, which will be processed by the miRNA machinery. siRNAs are typically created as single-stranded or double-stranded RNA, whereas shRNA starts out as a DNA sequence.
  38. what is CRISPR/Cas9
    A way to introduce mutations to specific sequences (i.e. gene targeting)
  39. CRISPR/Cas9 Components
    • gRNA – guide RNA. Sometimes called sgRNA (single guide RNA).
    • A short sequence that contains:
    • 1) Sequences of the gene you want to target
    • 2) Sequences to interact with Cas9 proteins
    • Cas9 – a protein complex with DNA endonuclease activity
    • Targeting construct – A fragment of DNA (i.e. not a circular plasmid). Contains the sequences you want to insert into the genome. The ends of the targeting construct have sequences that match the gene
    • you want to target (“homology arms")
    • Guide RNA + Cas9 will scan the genome and cut the DNA when the sequence matches the gRNA
  40. How does CRISPR/Cas9 work? (Step 1 & Step 2 a., 2b.)
    • 1) Guide RNA + Cas9 will scan the genome and cut the DNA where the sequence matches the gRNA
    • 2) During repair, two things can happen:
    • a) If there’s no targeting construct or other template for repair, then it will join the severed ends by nonhomologous end joining (NHEJ) which often shortens the DNA and usually inactivates the gene
    • b) If there’s a targeting construct or other template, the repair machinery will use that sequence to guide repair (homology directed repair), inserting the construct sequences into the gene
  41. You perform CRISPR/Cas9 gene targeting to insert a LacZ gene into
    Gene X in mice. You’re worried your construct may have also inserted
    elsewhere in the genome, so you sequence the genome of your mice.
    Which sequence will you focus on in your sequence file to further examine
    if an off-target integration has occurred?


    C. )
  42. How will you determine if you successfully inserted LacZ into Gene X?
    A. Use Xgal to measure β-gal activity in cells known to express Gene X.
    B. Use a Northern blot and probe for LacZ and Gene X and see if they
    have the same expression level.
    C. Perform an RT-PCR reaction with primers against lacZ and Gene X in
    cells known to express Gene X.
    D. Perform a qRT-PCR reaction with primers against lacZ and Gene X in
    cells known to express Gene X.
    E. Any of those would work.
    E.)
Author
jocelyn8
ID
347399
Card Set
Bio 99 Final Lec 14 (Eukatyotic)
Description
final
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