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A Model of a Current
When the two capacitor plates of a parallel-plate capacitor have been connected with a metal wire (______):
1. The net charge of each plate will ________ -the capacitor has been _______
2. The connecting wire gets _______
The motion of charges through a material is called a _______
- (conductor)
- decrease
- discharged
- warmer
- current
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The charges that move in a current are called the _____ ______. The charge carriers in metals are _______. It is the motion of the _______ _______, which are free to move around, that forms a current in the metal. A semiconductor is an intermediate case, with relatively few charge carriers, which can be either _______ or ______. In ionic solutions, the ______ ______ are ions that can be positive and negative
- charge carriers
- electrons
- conduction electrons
- negative or positive
- charge carriers
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Because the wire is connected between two points of _______ _______. There is an electric field in the wire pointing from ______ to ______ potential and it pushes _______ through the wire
The potential difference creates the ______ ______ that drives the current in the wire. Eventually, the plates will be completely discharged, resulting in the loss of what 3 things?
Label the potentials of each side
- different potential
- higher to lower potential
- electrons
- electric field
- No more potential difference
- No more field
- No more current
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The light bulb cannot ______ electrons nor ______ electrons. Every _______ entering the light bulb is matched by an ______ leaving the light bulb, and thus the currents on either side of a light bulb are ______
- destroy
- store
- electrons
- electrons
- equal
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Electric current that flows through a light bulb is analogous to _____ that flows through a ______:
Both water current and electric current are doing ______
The amount of ______ (electrons) leaving the ______ (light bulb) equals the amount of ______ (electrons) entering the ______ (light bulb).
Our first conclusion-Law of conservation of current states:
- water
- turbine
- work
- water
- turbine
- water
- turbine
- Law of Conservation of Current: the current is the same at all points in a current-carrying wire
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The amount of water leaving the turbine equals the amount ______; the number of electrons leaving the bulb equals the number ________
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Current is define as the motion of _______. It is the _______ that flow, not the ______. Current is the flow. Define current (mathematically)
- charges
- charges
- current
- Current: the rate at which charge moves through a wire in coulombs per second
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The current (I) is due to the motion of charges in the ______ ______. We imagine an area across the wire through which the charges move. In a time Δt, charge Δq moves through this area
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The current direction in a wire is from ________ to _______ potential, or in the direction of the ______ _____. It is conventional to assign the current the same direction as the flow of _______ ______. Current is measured in (_____/_____), which we define as an _______ (__).
State the equality of those units
Household currents are typically ~ 1A or 1 amp
For a steady current, the total amount of charge is delivered by a ______ during a ______ _____.
ΔQ = ____
- higher to lower potential
- electric field
- positive charges
- (coulombs/second)
- ampere (A)
- 1 ampere = 1 A = 1 coulomb/second = 1 C/s
- current (I)
- time interval Δt
- ΔQ = IΔt
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The zig-zag line represents the motion of charge carrier in a conductor. The net drift speed is ______. The sharp changes in direction are due to _______. The net motion of electrons is opposite the direction of the ______ ______. The random motion of the charge carriers is modified by the _____, and they have a drift velocity ________ the direction of the electric field
- small
- collisions
- electric field
- field
- opposite
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The total charge is the number of ______ multiplied by the _______ per ______, (__)
ΔQ = _______ (explain the components *2)
Define drift speed, vd, and state the formulas for:
vd = ______
ΔQ = ______
Iavg = _____ = _____
- carriers times charge per carrier (q)
- n = (number of charge carrier per unit volume)
- AΔx =volume
- q = e or charge from the electrons
- A = cross section area of the wire
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The current density (J) in a conductor is the _____ per unit ______:
J Ξ _____ = ______
Units: ______
The current density is in the direction of the _______ ______ ______
- current per unit area
- J Ξ I/A = nvdq
- A/m2
- positive charge carriers
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- I = nAvdq, so doubling diameter is proportional A2 (Cross-section so: Acircle = πr2) and doubling the drift speed is proportional to (2vd). So in total, we increase I by a factor of (22)(2) = 8
- D. 8
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B. Even if we don't know what a photoresistor is note we are changing the number of carriers. Light is turned off so n will decrease. Because n decreases in: I = (nAvdq)/A, the current will decrease
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C. What goes in must come out, the current is in series (they are all in one continuous path as opposed to in parallel, where they split with junctions). Identical light bulbs in series, must have the same brightness
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Define a Junction and state the mathematical requirements for its law of conservation
Formally name and explain the law
Label the diagram
- Junction: a point where a wire branches
- Law of conservation requires: ΣIin = ΣIout
- Kirchhoff's Junction law: the basic conservation statement is that the sum of the currents into a junction equals the sum of the currents leaving the junction
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- IA > IB
- IA = 2 + IB.........(1)
- IC > IB
- 3 = IC - IB.......(2)
- from 1 & 2
- IA + 3 = 2 + IC
- IC - IA = 1
- Ic > IA
- therefore
- Ic > IA > IB
option C
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- D. Sum of Iin = 7A
- Sum of Iout = 9A
- so the one coming from the right has to be 2A to make up the difference
- Its based on the direction of the current, its always one way traffic from high to low
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The inner workings of a battery act like a _______ ______ between the two terminals. Charges are removed from the _______ terminal and "lifted" to the _______ terminal. Once a charge reaches the _______ terminal, it can flow downhill through the wire until it reaches the ________ terminal again. The flow of charge in a continuous loop is called a ________ ________.
- charge escalator
- negative terminal
- positive terminal
- positive
- negative
- complete circuit
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Once the charges reach the ______ terminal, they "____ _____" through the wire back to the ______ terminal.
The charge escalator "lifts" charges from the ______ terminal to the _______ terminal. Charge (q) gains energy ΔU = ______
Identify the positive and negative terminal (state formula for U at each), where U is increasing, where it is decreasing and what is the direction of I
- positive
- "fall downhill"
- negative
- negative
- positive
- ΔU =qΔVbat
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The charge escalator in a battery is powered by ______ _____ (explain-2-story).
A dead battery is one in which the supply of chemicals has been ________.
The potential difference established by a device, such as a battery, that can actively separate charge is called an _____ (__) and its units are _____
- chemical reactions
- ☞Chemicals called electrolytes are sandwiched between two electrodes of different material
- ☞The chemicals react and move the positive ions to one electrode, the negative ions to the other.
- exhuasted
- emf (ε)
- volts
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A source of emf (________ force) is an entity that maintains the ______ ______ of a circuit. The _______ will normally be the source of energy in the circuit.
_______ are also sources
A capacitor ______ separated charges, but has no means to do the ________. A charged capacitor has a(n) ______ ______ but not a(n) _______
The emf (ε) sources supplies _____ it does not apply a force to the ______
- emf, ε, (electromotive force)
- potential difference
- battery
- Generators
- stores
- separation
- potential difference
- emf
- energy
- circuit
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Briefly explain whether or not an emf is a force in the classical sense (tension, gravity, etc). Which qualify as an emf and why: battery vs capacitor
- emf is technically not a force, it is more like an electron gradient able to generate charge separation
- So a battery is an emf but a capacitor isn't because it can't separate the charge on its own
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- B. I = nAvdq, increase in thickness will be an increase in area
- Can't be C, you'd need a higher emf, a lower will achieve the opposite
- Can't be D, no change will occur
- Can't be E or A
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