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Calculating the Electric Potential
Knowing the potential energy, we can calculate the electric potential of a charge q at a point using what equation?
V = Ue/q
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The parallel-plate capacitor creates a uniform electric field (state the formula)
The plates have area A and separation d. Let U e = 0 when a mobile charge q is at the negative plate (x = ___). The charge's potential energy at any other position x is then the amount of work necessary to move the charge from the ______ ______ to that position
The hand does work on q to move it ______ against the field, thus giving the charge electric potential energy
- E = Q/ε0A
- (x = 0)
- negative plate
- uphill

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The hand push the charge q towards the positive plate at a constant speed. Thus, F hand = ____ = ____
State the formula for the work to move the charge to position x:
W (2)
State the formula for the work to move the mobile charge to position x within the contex of potential energy:
W (2)
- Fhand = Fe = qE
- W = (force)(displacement) = (Fhand)(x) = (qE)(x)
- W = ΔK + ΔUe = (qE)(x)
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The electric potential of the parallel-plate capacitor at position x, measured from the negative plate (U e = ___, V = ___), is:
State the formula for V (3)
The electric potential increases linearly from the ______ plate (x = ___) to the ______ plate at (x = ___)
The potential difference ΔV c between the two capacitor plates is:
ΔV c = _______ = _____
- (Ue = 0, V = 0)
- V = Ue/q = Ex = (Q/ε0A)(x)
- negative plate (x = 0)
- positive plate (x = d)
- ΔVc = V+ - V- = Ed
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A 2-D equipotential map is represented below. The green dashed lines are _________ lines or simply _________.
- equipotential lines
- equipotential
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To find the electric potential due to a single fixed charge q, we first find the electric potential energy when a second charge q' is a distance r B away from q
ΔU e = ______
Take (U e) A = 0 to be at a point infinitely far from q (i.e. r A → ∞) for convenience. This is a good reference point as the influence of the point charge q goes to _____ as we get _____ far from the charge
- ΔUe = Wby the hand
- zero
- infinitely
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The force on q' gets larger as it approaches q. Thus, work done is not by a constant force and cannot use the equation W = Fd to find the work for a ______ ______ q'
moving charge q'
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An exact calculation finds the electric potential energy of two point charges separated by distance r is:
U e = ______
In the case where q and q' are opposite charges, the potential energy of the charges is _______. q' _______ toward fixed charge q. U elec = 0 when q' is ______ far from q. As q' approaches q it gains ______ energy and loses ______ energy
The y-axis is U elec
- Ue = (ke)(qq'/r)
- negative
- accelerates
- infinitely
- kinetic energy
- potential energy

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For a charge q' that is a distance r from a charge q, the electric potential is related to the potential energy by V = ____.
The electric potential at distance r from a point charge q is:
V = ____ = ____ = ____
Only the source charge appears in this expression. (The source charge creates the _______ _______ around it)
- potential energy
- V = Ue/q'
- electric potential
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Electric potential at distance r from a point charge q
Restate the formulas for V(3)
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- C. assume charges are positive unless told otherwise.
- Potential at point A: VA = keQ/rA
- Potential at point B: VB = keQ/rB
- VB/VA = (keQ/rB)(rA/keQ) = rA/rB = (1mm/3mm) = 1/3
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The electric potential at a distance r > R from the center of a sphere of radius R and with charge Q is the same as the _____ _____ at a distance r from a point charge.
- electric potential

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The potential V0 is the potential at the surface of the charged sphere
V0 = _____ = _____
The charge for a sphere of radius R is therefore:
Q = _____
The potential outside a charged sphere:
V = ______ = _______ = _____
The potential ______ _____ with distance from the center
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- D. V = keQ/r = (R/r)(V0)
- V0= [(V)(r)]/(R) = (30*15)/5 = 90V
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V is constant everywhere on the surface of a charged conductor in equilibrium. ΔV = ___ between any two points on the surface. No work is required to move a _____ _____ between any two points on the surface. The surface of any charged conductor in electrostatic equilibrium is an ________ ______. Why is it that the electric potential is constant everywhere inside the conductor and equal to the value at the surface.
- ΔV = 0
- test particle
- equipotential surface
- Because the electric field is zero inside the conductor
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Consider a solid metal conducting sphere, Radius is R, total charge is Q. The electric potential is a function of ____. The electric field is a function of ____
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Suppose there are many source charges, q1, q2... the electric potential V at a point in space is the ____ of the _______ due to each charge. So V = _____ = _____
Define ri
The electric potential is a simple _____ ____ which is easier to find
- sum of the potentials
- ri: the distance from charge qi to the point in space where the potential is being calculated
- scalar sum
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Label the diagram (4)
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Vector E and V are not two distinct entities, but instead, two different perspectives or two different mathematical representations of?
Vector E at a point is _______ to the equipotential surface at that point
Vector E points in the direction of _______ potential
- Two different perspectives or two different mathematical representations of how source charges alter the space around them
- perpendicular
- decreasing
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Vector E is ______ to the equipotential surface everywhere. Vector E points ______ in the direction of ______ V. The field strength is ________ ________ to the spacing d between the equipotential surfaces
- perpendicular
- downhill
- decreasing
- inversely proportional

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A positive charge speeds up as it moves from ______ to ______ potential. The work required to move a charge, at a ______ _____, in a direction opposite the electric field is:
W = ______ = _____ = _____
Constant speed → F hand = ____ = ____
Thus  = ____ (explain d)
- higher to lower potential
- constant speed
- W = Fhand = ΔUe = qΔV
- Fhand = Fe = qE
, where d is the distance between the two equipotential surfaces
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D. ΔU = eΔV = e(100V) = 100 eV
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Below are the three important arrangements of charges. Both electric field lines and equipotentials are shown. Remember the electric field vector is ______ to the equipotential surface.
In point charges and electric dipoles, field lines are everywhere _________ to equipotentials. The electric field is _______ where the equipotentials are closer together. For electric dipoles in a Parallel-plate capacitor, field lines point from ______ to ______ potential. For the capacitor, the field is ______ and so the equipotential spacing is _______
- perpendicular
- perpendicular
- stronger
- higher to lower potential
- uniform
- constant

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- E field always points from high to low so possibly B E C
- As the E Field goes up, the distance between the lines gets smaller and smaller so C
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- A: Ans = B Distance is the shortest so E field is the strongest
- B: Ans = D
- C and D check notes
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Properties of a conductor in electrostatic equilibrium:
1. All excess charge is on the ______
2. The electric field inside is ______
3. The exterior electric field is ______ to the surface
4. The electric field strength is largest at the ______ ______
- surface
- zero
- perpendicular
- sharp corners

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- Wire makes it so the potential is the same in both spheres.
- v1 = kQ1/r1
- v2 = kQ2/r2
- so:
- Q1/r1 = Q2/r2
- 2nC/1cm = Q2/2cm
- Q2 = 4 nC
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The electrical activity of cardiac muscle cells makes the beating heart an ______ ______. A resting nerve cell is _______; the outside is ______ and the inside is ________. Initially, all muscle cells in the heart are polarized, until an electrical impulse from the heart triggers the cells to ______, moving ions through the cell wall until the outside becomes ______. This causes the muscle to contract
- electric dipole
- polarized
- positive
- negative
- depolarize
- negative
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The depolarization of one cell triggers a wave of ________ to spread across the tissues of the heart. At any instant, a boundary divides the negative charges of _______ cells from the positive charges of cells that have not yet ________ in the heart. This separation of charges creates an electric dipole and produces a ______ ______ field and ______
- depolarization
- depolarized
- depolarized
- dipole electric field and potential
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The boundary between polarized and depolarized cells sweeps rapidly across the atria. At the boundary there is a charge separation. This creates an ______ ______ and an associated dipole moment
Label the diagram
- electric dipole

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A measurement of the electric potential of the heart is an invaluable diagnostic tool. The potential difference in a patient is measured between several pairs of ________. A chart of the potential differences is the __________, also called an _____ or an _____. With each heart beat, the wave of depolarization moves across the heart muscle. The dipole moment of the heart changes _______ and _______
- electrodes
- electrocardiogram
- ECG or an EKG
- magnitude and direction
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The records of the potential difference between the two electrodes is the ________.
The potential differences at a, b, and c correspond to those measured in the three stages shown to below
- electrocardiogram

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