-
Electronic noise is a random fluctuation in an electrical signal, a characteristic of ____ electronic circuits.
all
-
Noise generated by electronic devices varies greatly, as it can be produced by ___ effects.
several different
-
Thermal noise is _____ in circuits above absolute-zero temperature (e.g. all ordinary circuits).
unavoidable
-
Except for thermal noise, the other types of noise depend on
device type
-
Noise is considered
an undesirable random signal
-
Noise and distortion are the same thing
false
-
White noise refers to a statistical model for signals and signal sources, rather than to any specific signal.
true
-
White noise sounds like (hear it on Wikipedia):
the bottom of a large waterfall
-
White noise on an oscilloscope looks like
a fuzzy caterpillar
-
Thermal noise exists in an electrical conductor ONLY when electrical current is not zero.
false
-
Thermal noise exists in an electrical conductor when electrical current is zero.
true
-
Thermal noise exists in an electrical conductor when electrical current is zero or not zero
true
-
When the temperature is above absolute zero, thermal noise is
unavoidable
-
Thermal noise is generated by the random thermal motion of electrons, which happens regardless of any applied voltage.
true
-
The theoretical model that closely approximates thermal noise is ____ noise.
white
-
There is no dominant frequency in white noise, because all frequencies are present simultaneously.
true
-
Thermal noise _____ be reduced by cooling the circuit.
can
-
When two wires are close to each other, the signal in one wire can show up in the other.
- both of these
- true, and this is called crosstalk.
- true, and can be explained by capacitive coupling.
-
Other types of noise that can show up in the maglev circuit include: industrial, atmospheric, and interfence such as power lines.
true
-
Other types of noise that can show up in the maglev circuit include: solar, cosmic, and extraterrestial.
true
-
For initial tuning, both P-pot and D-pot should be turned to
zero
-
r initial tuning, ______ should be increased _____.
P-pot, first
-
For initial tuning, the P-pot should be increased until the globe bounces off the hand
a little
-
During levitation, the P-amplifier provides ____ and the D-amplifier provides ___.
lifting, damping
-
Occasionally the globe continues to strike the magnet and bounce off. While bouncing, adjusting the P & D pots can halt this condition.
false
-
For initial tuning, begin by holding the top of the globe ____ the balance line.
at
-
The levitation current is expected to be _____amps.
.3 to 1
-
The levitation current magnitude depends mostly on the
air gap
-
The globe is constructed from
steel
-
The electromagnet consists of _____ magnet wire.
- either of these
- 1000 turns of 18 or 20 gage
-
The diode across the electromagnet protects the ______ from large voltage spikes when electromagnet current is halted abruptly.
opamps
-
The air gap is the distance between the balanced globe and bottom the electromagnet, and is adjusted by
the nut on the carriage bolt
-
The power transistor that regulates the electromagnet current is
mounted on an aluminum heat sink on the back of the support stand
-
Twisting the red/yellow/black wires from the power supply, instead of untwisted wires
reduces noise in those wires
-
Optimal orientation of heat-sink fins is
vertical
-
The maglev system is robust if it can withstand physical and electrical disturbances.
true
-
e best way to monitor electromagnet current is with a
power supply that shows the current continuously
-
The opamps require ______ volts.
both +15 and -15
-
The photo diode and photo transistor require _____ volts.
5
-
If 15 volts is applied to the photo diode and photo transistor, they will be destroyed.
true
-
Required wire colors are red for +15v; Yellow for -15v; Black for ground; & Green or Blue for 5v.
true
-
The metal globe is lifted by
a magnetic field
-
The magnetic field is controlled by
an analog PD controller
-
The globe position is sensed by an IR LED and IR transistor.
true
-
As the globe is lifted higher, the IR-transistor current
decreases
-
As the IR transistor current increases, the voltage at F
increases
-
Ideally, the voltage at A is ____ the voltage at F.
the same as
-
The maximum voltage at A will be approximately _____ volts.
5
-
The minimum voltage at A will be _____ volts.
0
-
If the voltage at A (V_A) is railed (i.e. approximately + or -15 volts), a problem is indicted in the ____ opamp.
1st
-
While the globe is levitating, the ideal voltage V_A will be nearly ____ volts.
2.5
-
If the proportional potentiometer (P-pot) is 2k Ohms, and V_A=2 volts, V_B will be ____ volts.
-4
-
If V_A is a steady 2 volts, then V_C will be _____ volts, independently of D-pot.
0
-
If V_A is increasing, then V_C will be ______voltage.
some negative
-
V_M will be nearly _____volts, which is independent of V_B and V_C.
0
-
The output of opamp-4 (V_D) is
-(VB+VC)
-
If 15 volts is connected to the IR LED or IR transistor, the result will likely be failure of the IR LED or IR transistor.
true
-
If R6 were zero Ohms (a wire), the differentiator would be an ideal differentiator.
true
-
R6 is not zero, which makes opamp-3 a practical differentiator. A _____ can demonstrate that opamp-3 is only a differentiator at low frequency.
Bode plot
-
If 5 volts is connected across the IR LED, because R1 is omitted, the result will likely be failure of the IR LED.
true
-
If red wires are used exclusively for +15 volts and yellow wires for -15 volts, debugging will be greatly facilitated.
true
-
Fig 1400a indicates an open-loop transfer function (TF) of
GH
-
Fig 1400a indicates an closed-loop transfer function (TF) of
G/(1+GH)
-
The _____ is used to determine closed-loop gain margin (CLGM) and closed-loop phase margin (CLPM).
open-loop TF
-
CLGM and CLPM are determined from the _____ of the open-loop transfer function
Bode plot or Nichols plot
-
The CLGM is determine by the OL gain relative to the
0 dB gain at -180 deg phase
-
The CLPM is determined by the OL phase relative to the
-180 deg phase at 0 dB gain
-
CLGM and CLPM can be observed most easily on the
Nichols plot
-
The center of the Nichols plot
is 0dB and -180 deg
-
Desirable CLGM and CLPM in the aerospace industry is 10 dB (3.16) and 30 deg.
true
-
The CL system will be marginally stable if the OL gain increases by the
CLGM
-
e CL system will be unstable if the OL gain increases by more than the
CLGM
-
The CL system will be marginally stable if a time delay exists in the loop corresponding to
CLPM
-
The CL system will be unstable if more time delay exists in the loop corresponding to
CLPM
-
The MATLAB function _____ draws the OL-system Bode plot and shows the CLGM and CLPM.
margin(n,d)
-
The MATLAB function nichols(n,d) draws the OL-system Nichols plot and shows the CLGM and CLPM.
lse because it does not print the CLGM and CLPM.
-
The MATLAB function nichols(n,d) draws the OL-system Nichols plot and the CLGM and CLPM are easily visualized relative to the 0 dB and -180 deg point.
true
-
The Nichols plot of the OL TF shows the frequency content just like the Bode plot.
false
-
The vertical axis ______ of the Nichols plot is the same as one Bode plot axis.
gain (dB)
-
The horizontal axis _______ of the Nichols plot is the same as one Bode plot axis.
phase (degrees)
-
TF=g. The gain of this transfer function (TF) is
gdB at all frequencies
-
TF=g. The phase is
0 deg at all frequencies
-
TF=1/s. The gain is
-20dB/decade with 0dB gain at 1 rad/sec
-
TF=1/s. The phase is
-90 deg at all frequencies
-
TF=1+s/w1, which is a LEAD (not LAG) TF. The gain is
0 dB at frequencies below the corner frequency
-
TF=1+s/w1, which is a LEAD (not LAG) TF. The gain is
20dB/decade above the corner frequency
-
TF=1+s/w1, which is a LEAD (not LAG) TF. The phase is
0 deg below 0.1*corner and 90 deg above 10*corner frequency
-
TF=1+s/w1, which is a LEAD (not LAG) TF. The phase is
45 deg/decade between 0.1*corner and 10*corner frequency
-
TF=1/(1+s/w2), which is a lag TF. The gain is
0 dB at frequencies below the corner frequency
-
TF=1/(1+s/w2), which is a lag TF. The gain is
-20dB/decade above the corner frequency
-
TF=1/(1+s/w2), which is a lag TF. The phase is
0 deg below 0.1*corner and -90 deg above 10*corner frequency
-
TF=1/(1+s/w2), which is a lag TF. The phase is
-45 deg/decade between 0.1*corner and 10*corner frequency
-
TF=g is a ______ transfer function.
gain
-
TF=1/s is a ______ transfer function.
integrator
-
TF=1+s/w1 is a ______ transfer function.
1st-order lead
-
TF=1/(1+s/w1) is a ______ transfer function.
1st-order lag
-
TF=s is a ______ transfer function.
differentiator
-
TF=s. The gain is 20 dB/decade at all frequencies and has 0 dB gain at 1 rad/sec.
true
-
TF=s. The phase is constant 90 deg at all frequencies.
true
-
The total gain Bode asymptotic plot is the _____ of the components.
sum
-
The total phase Bode asymptotic plot is the _____ of the components.
sum
-
Asympotic Bode plots are
straight-line approximations
-
Deviations of asymptotic Bode plots from actual Bode plots occur at the
corners
-
Asymptotic Bode plots can be sketched from the
system transfer functions
-
The system TF must be written in _____ in order to manually sketch asymptotic Bode plots
factored-polynomial form
-
G(s)=1/(s+a), and in Bode-plot form, G(s)=
(1/a)/(1+s/a)
-
G(s)=1/(s(s+a)), and in Bode-plot form, G(s)=
(1/a)/(s(1+s/a))
-
G(s)=1/((s+b)(s+a)), and in Bode-plot form, G(s)=
(1/(a*b))/((1+s/b)(1+s/a))
-
G(s)=1/(s^2+a*s+b), and in Bode-plot form, G(s)=
(1/b)/(1+a*s/b+s^2/b)
-
G(s)=(s+a)/(s+b), and in Bode-plot form, G(s)=
(a/b)(1+s/a)/(1+s/b)
-
G(s) = a*(s+w1)
first-order lead
-
G(s) = a/(s+w1)
first-order lag
-
G(s) = a / ( (s+w1) * (s+w2) )
double lag
-
G(s) = a/(s^2 + b*s + w1^2)
second-order lag
-
-
-
-
The first-order lead has a Bode-gain slope of _____ after the corner.
20dB/decade
-
The first-order lag has a Bode-gain slope of _____ after the corner.
-20dB/decade
-
-20dB/decade
-20dB/decade
-
The second-order lag has Bode-gain slope of ____ after the corner
-40dB/decade
-
The delay has Bode-phase that _____ as frequency increases.
decreases
-
The delay TF has Bode-gain that _____ as frequency increases.
remain constant
-
For a Bode phase of 85 degrees, and an input of A*sin(w*t), the output at that frequency would be
B*sin(w*t+85 deg)
-
For a Bode gain of -20 dB, and an input of 30sin(w*t), the output at that frequency would be
3sin(w*t+theta)
-
For a Bode gain of -20 dB, the system numeric gain at that frequency is
0.1
-
Bode plots show output and input sine wave ratios at different frequencies.
true
-
Bode plots show output and input sine wave ratios at different frequencies.
true
-
Bode plots show how sine waves are affected by some linear system.
true
-
The phase-Bode plot for a high-pass TF shows _____ phase at low frequency and ______ phase at high frequency.
high, low
-
The gain-Bode plot for a high-pass TF shows _____ gain at low frequency and ______ gain at high frequency.
low, high
-
The phase-Bode plots produced by MATLAB are
phase in degrees vs frequency in rad/sec
-
The gain-Bode plots produced by MATLAB are
gain in dB vs frequency in rad/sec
-
Both gain and phase-Bode plots are ______ graphs.
log-linear
-
Both gain and phase Bode-plots are ______ graphs.
semilog
-
In the gain and phase Bode plots, the _____ axes are different in both plots.
vertical
-
The Bode plot frequency axis is a
log scale
-
The Bode plot frequency axis is the
horizontal axis and is the same for both plots
-
The bottom Bode plot is usually (like produced by MATLAB)
system phase vs frequency
-
The top Bode plot is usually (like produced by MATLAB)
system gain vs frequency
-
-
A Bode plot is a description of a
linear time invariant system (LTI)
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