Algebra - Polynomials Multiplication

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*Each term in the first polynomial must be multiplied by each term in the second.

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*Each term in the first polynomial must be multiplied by each term in the second.

*Each term in the first polynomial must be multiplied by each term in the second.

x(5x2)+x(-2x)+x(-6)+4(5x2)+4(-2x)+4(-6)

5x³-2x²-6x+20x²-8x-24

• difference
• squares
• perfect
• square

a²-ab + ab -b²



(difference of squares)

• (a+b)(a+b)
• a²+ab+ab+b²
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(perfect square trinomial)

• difference
• squares
• 

• perfect
• square
• 
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V= (x+4)(x+4)(x+4)

Step 1: Multiplying from left to right, you notice that you're squaring a binomial. So, you'll get a perfect square trinomial.

• Step 2: Rewrite the equation:
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Step 3: Multiply each term in first parentheses by each term in the 2nd.

x²*x+x²*4+8x*x+8x*4+16*x+16*4

x³ + 4x² + 8x² + 32x + 16x + 64

Step 4: Combine like terms:

V =

Once you recognize the conjugate, you know you will end up with a difference in squares, so you don't have to multiply the "long way".

Once you recognize the conjugate, you know you will end up with a difference in squares, so you don't have to multiply the "long way".

We know that the result will be a perfect square trinomial. So, you don't have to multiply (a+b)(a+b) the long way.

 (2x)² +2(2x)(5) + (5)²

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• SAME AS:

We know that the result will be a perfect square trinomial. So, you don't have to multiply (a+b)(a-b) the long way. Just remember to put the negative sign in front of the middle term.

(3y²)² - 2(3y²)(7w) + (7w)²