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exam #4
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Kw or constant for water
1x10
^{14}
M
^{2}
Sea level = 1 atm =?
STP
760 torr =
760 mmHg =
101.325 Kpa =
14.696 psi
Kelvin to Celcius
0 C = 273 K
0K = -273.15 C
room temp =
25 C = 298 K
Charles Law
volume - temp
V
_{1}
T
_{2}
= V
_{2}
T
_{1}
Boyles Law
pressure - volume
P
_{1}
V
_{1}
= P
_{2}
V
_{2}
Combined Gas Law
P
_{1}
V
_{1}
T
_{2}
= P
_{2}
V
_{2}
T
_{1}
Ideal gas law
PV = nRT
P= pressure atm
V= volume liters
n= #moles
R= gas constant = 0.0821(L.atm/mol.K)
T= temp Kelvin
R, Gas constant =
0.0821
Molecular weight and density equation
D=(MP)/(RT)
note
: D=m/v
M= molar mass g/mol
D= density = mass/volume
R= gas constant = 0.0821
T= temp K
P= pressure atm
also M=DRT / P
Grahams Law
rate of gas a / rate of gas b =
√(molar mass b / molar mass a)
avagadros number
6.02x10
^{23}
moles to liters
1 mole = 22.4 L
Author
dvdromm
ID
243713
Card Set
exam #4
Description
chem
Updated
2013-10-29T20:31:26Z
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