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    TIR occurs when the first medium is denser than the second medium. Choices I and II definitely won't work. By process of elimination.
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    Cycloheptane is a 5-membered ring, which is very stable. It will react more willingly with O2 and undergo violent combustion to produce a more stable CO2.
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    • Use angular numbers, but just apply them to translational motion equations. 
    • wf+wi/2 = 0/t
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    Yes, the force of friction would have to change...but the question is asking about WORK! The work done by friction must equal the kinetic energy in order to stop the child, regardless of distance.
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    The total water needed would be 250, but you already have 100mL of water!!
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    This is a torque problem. Assuming that the end of the plank of the groung is the AOR, the only other force acting on the plank would be gravity - presumably in the middle of the plank at L/2. In order to balance this torque, you should have a force of mg/2 since you're L away from the AOR.
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    • Apparent weight is always the normal force. Since both Fb and FN are in the same direction, N = mg - Fb. 
    • Since the object is sunken, Fb = Vobj x pwater x g. Just use the data to get Vobj, but don't forget that pwater = 1g/mL or 1000kg/L.
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    • Static friction is what helps us to walk! 
    • Kinetic friction = slipping, Static friction = sliding
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    Remember that the tensions and accelerations of the system is the same, but don't forget to consider the direction in which the vectors are pointing!
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    An example of solving a nernst problem
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    The friction will act to prevent the cart from moving up the track - so the cart will not move as far up the track.

    Because the car will not move as far up, the carts will experience a greater magnitude to acceleration, since the acceleration vector is pointing against the direction of movement.
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    Use the ICE Equation here!!!
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    In this calorimetry experiment, we're given a solution of HCl along with the specific heat of HCl. 

    MgO is added to HCl. To get the answer, we set up the q=mcT equation, which will only give J. Then to incorporate the addition of MgO, we divide my the moles of MgO used.
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    Note that the question is asking about the VOLTAGE through the capacitor and the CURRENT through the resistors. 

    The voltage will increase, while the current will build up across the capacitor and increase instead through the resistors.
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