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what can dif be used for
to find the gradient of a curve at a given coordinate
motion of a particle
turning points
rate of change
work out maximum and minimum problems
to find the gradient of a curve at a given coordinate
dif
put x value into dy/dx equation
to find turning points of an equation
dif
dy/dx = 0
solve to find x
put x value into original equation to find y
to find out whether maximum or minimum
dif dif
put x value into dif dif
if this > 0 minimum , < 0 maximum
find the maximum/minimum in problems
dif
dy/dx = 0 to find letter
may need to put letter value back into the original equation to find area for eaxmple
square root of a positive number
can be positive or negative
motion of a particle
original equation = displacement or s in metres (M)
dif = velocity in m/s
dif dif = acceleration in m/s2
>
greater than
<
less than
double dash ones
mean
less than or equal to for double dash <
more than or equal to for double dash>
with inequalities whenever you multiply or divide by a negative number
flip the inequality sign
x2 < 16
x < 4
x > -4
open circle means
not included in the solution
shaded circle means
included in the solution
graphical inequalities method
convert each inequality into an equation
draw the graph for each equation (if the inequality is
work out which side of each line you want by putting x = 0 into the inequality if it gives a false answer the origin is on the wrong side of the line
shade the region this gives u
Author
Anonymous
ID
213205
Card Set
GCSE Maths
Description
revision
Updated
2013-04-13T13:54:02Z
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