A basketball team sells tickets that cost $10, $20, or, for VIP seats $30. The team has sold 493 tickets overall. It has sold 187 more $20 tickets than $10 tickets. The total sales are $8870. How may tickets of each kind have been sold?
This ends up being just a substitution problem with three equations. First find the equations,
- 1. x+y+z=493
- 2. 10x+20y+30z=8870
- 3. y=x+187
Then substitute in y where it needs to be, getting rid of y, then use the substitution method to get rid of the x or z and give the number up by itself. Solve like any other substitution problem. :)