genchem exam 1 ch 1 review

Home

Get App

Create

x ft in 1 mile

5280 ft in 1 mile
x km in 1 mile

1.609 km in 1 mile
x cm in 1 inch

2.54 cm in 1 inch
1 dm^3
- = 1 liter
- also 10^-3 m^3
NH4+

ammonium
H3O+

Hydronium
Acetate
- C2H3O2-
- CH3COO-
Cyanide

CN-
Hydroxide

OH-
HypoChlorite

ClO-
Chlorite

ClO2-
Chlorate

ClO3-
Perchlorate

ClO4-
Nitrite

NO2
Nitrate

NO3-
Permanganate

MnO4-
Carbonate

CO3 2-
Hydrogen BiCarbonate

HCO3-
Chromate

CrO4 2-
Dichromate

Cr2O7 2-
Peroxide

O2 2-
PO4 3-

Phosphate
Hydrogen Phosphate

HPO4 2-
Dihydrogen phosphate

H2PO4-
Sulfite

SO3 2-
Sulfate

SO4 2-
Hydrogen Sulfate

HSO4-
AgI

Silver(I)Iodide
VF3

Vanadium(III)Fluoride
In2O3

Indium (III) Oxide
FeF3

Iron (III) Fluoride
Alkali Metals
- Lithium
- Sodium
- Potassium
- Rubidium
- Cesium
- Francium
Alkali Earth Metals
- Beryllium
- Magnesium
- Calcium
- Strontium
- Barium
- Radium
Molarity

Moles of Solution/Liters
Fractional Abundance

Substance1x + (1-x)substance2 = average
F to C

substract 32, multiply by 5/9
C to F

Multiply by 9/5, Add 32
C to K

Add 273.15
Mass of Composition in Sample 2

(Mass of Composition in Sample1/Mass of Sample 1) * Mass of Sample 2
What was the percent yield?
- 1. find out moles A
- 2. find atomic/molecular mass of target
- 3. consider molar ratio
- 4. multiply moles * molecular mass
- Gives theoretical yield
Limiting Reactant Problems
- Convert g reactants to moles
- Consider molar ratio between reactants
- Consider molar ratio between limiting and product
- Multiply/Divide if necessary
Neutralization
- Convert target that was neutralized to moles (divide by molar mass)
- Consider mole ratio between target and neutralizer
- Multiply/Divide if necessary
- Divide by volume given

Author

esmenikmati

203803

Card Set

genchem exam 1 ch 1 review

Description

chapter1

Updated

2013-03-02T19:30:52Z

Show Answers