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genchem exam 1 ch 1 review
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x ft in 1 mile
5280 ft in 1 mile
x km in 1 mile
1.609 km in 1 mile
x cm in 1 inch
2.54 cm in 1 inch
1 dm^3
= 1 liter
also 10^-3 m^3
NH4+
ammonium
H3O+
Hydronium
Acetate
C2H3O2-
CH3COO-
Cyanide
CN-
Hydroxide
OH-
HypoChlorite
ClO-
Chlorite
ClO2-
Chlorate
ClO3-
Perchlorate
ClO4-
Nitrite
NO2
Nitrate
NO3-
Permanganate
MnO4-
Carbonate
CO3 2-
Hydrogen BiCarbonate
HCO3-
Chromate
CrO4 2-
Dichromate
Cr2O7 2-
Peroxide
O2 2-
PO4 3-
Phosphate
Hydrogen Phosphate
HPO4 2-
Dihydrogen phosphate
H2PO4-
Sulfite
SO3 2-
Sulfate
SO4 2-
Hydrogen Sulfate
HSO4-
AgI
Silver(I)Iodide
VF3
Vanadium(III)Fluoride
In2O3
Indium (III) Oxide
FeF3
Iron (III) Fluoride
Alkali Metals
Lithium
Sodium
Potassium
Rubidium
Cesium
Francium
Alkali Earth Metals
Beryllium
Magnesium
Calcium
Strontium
Barium
Radium
Molarity
Moles of Solution/Liters
Fractional Abundance
Substance1x + (1-x)substance2 = average
F to C
substract 32, multiply by 5/9
C to F
Multiply by 9/5, Add 32
C to K
Add 273.15
Mass of Composition in Sample 2
(Mass of Composition in Sample1/Mass of Sample 1) * Mass of Sample 2
What was the percent yield?
1. find out moles A
2. find atomic/molecular mass of target
3. consider molar ratio
4. multiply moles * molecular mass
Gives theoretical yield
Limiting Reactant Problems
Convert g reactants to moles
Consider molar ratio between reactants
Consider molar ratio between limiting and product
Multiply/Divide if necessary
Neutralization
Convert target that was neutralized to moles (divide by molar mass)
Consider mole ratio between target and neutralizer
Multiply/Divide if necessary
Divide by volume given
Author
esmenikmati
ID
203803
Card Set
genchem exam 1 ch 1 review
Description
chapter1
Updated
2013-03-02T19:30:52Z
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