The flashcards below were created by user
daynuhmay
on FreezingBlue Flashcards.
-
- 1o alcohol -> aldehyde
- mild oxidizing agent
- 1. PCC, 2. CH2Cl2
-
- 1o alcohol -> carboxylic acid
- strong oxidizing agent
- CrO3, H2SO4, H2O
- or
- K2Cr2O7,H2SO4, H2O
-
- carboxylic acid->1o alcohol
- strong reducing agent
- LiAlH4
-
- aldehyde -> alcohol
- mild reducing agent (only reacts w/ aldehydes & ketones)
- NaBH4
-
reagents that make -OH a good leaving group
- 1) TSCl, pyr (replaces OH with OTS)
- 2) SOCl2, pyr
- 3) PBr3 (replaces OH with Br)
-
NaH (2 functions)
- 1) deprotonates OH to O-
- 2) forms alkene at site of halogen (E2 rxn)
-
under acidic conditions, attack occurs at the ____ hindered side
MOST hindered
-
under basic conditions, attack occurs at the _____ hindered side
LEAST hindered
-
-
non-nucleophilic acids (3)
-
MgBr+-R-
- Grignard reagent
- strong base, carbon nucleophile
- attacks less hindered side of epoxide
- useful in adding hydrocarbons to a molecule
-
LiAlH4 (2 functions)
- 1) strong reducing agent (carboxylic acid -> alcohol)
- 2) breaks open epoxide without adding anything to it
-
form less substituted alkene with ____ bulky base
-
dehydration (E1) rxn
H2SO4, H2O, heat
-
- hydrogenation
- syn addition
- H2, Pt catalyst
-
dihalogenation of an alkene
1) 1st halogen forms a(n) ____
2) 2nd halogen (or nucleophilic solvent) attacks ____ hindered side
- 1) 3-membered ring across alkene double bond
- 2) more hindered side
-
Markovnikov's Rule
H from reagent added to C (of alkene) w/ most H's
-
1. BH3
2. 3H2O2, 3NaOH
- hydroboration
- adds H to more and -OH to least substituted side
- anti-Markovnikov addition (in syn fashion)
-
1. Hg(OAc)2, H2O
2. NaBH4
- oxymercuration-demercuration (reduction)
- Markovnikov addition of H-OH (in anti fashion) -> OH added to more substituted side
-
KMnO4, H2O, NaOH
- dihydroxylation
- syn addition of 2 -OHs across alkene
-
1. O3
2) Zn, AcOH
- ozonolysis
- cleavage at alkene bond resulting in 2 aldehydes
-
mCPBA (w/ an alkene)
- epoxidation
- formation of epoxide at site of C=C
- attacks above and below
-
H 2SO 4, H 2O,  (added to alcohol)
OH -> C=C
-
H2SO4, H2O (added to alkene)
OH added to more hindered side (Markovnikov addition)
|
|