MCAT Physics

x=x₀+v₀t+1/2at²

Where x = distance (meters), v = velocity(meters/sec), a = acceleration(meters/sec/sec or meters/sec²), and t = time(sec).

Where (mu) is the frictional coefficient and Fn is the normal force.

v = d / t

• d = vt
• d = v_avg t 
• d = v_initial t + 1/2 a t²

d = 1/2 a t ²  <--when at rest

v_final² = v_initial² + 2 a d

v_yinitial = v sin (theta)

v_x = v cos (theta)

t_up = 0 - v_yinitial / g 

Where g = gravity

y_max = v_yinitial/ 2 * t

W = mg

F = G * m₁ m₂ / r²

Where G = gravitation constant, m₁ = mass of 1st object, m₂ = mass of 2nd object, and r = radius

a = v² / r

F = m a_c

W = f d

Where force is only in the direction of motion

KE = 1/2 mv²

PE = mgh