Enthalpy of chemical system decreases as /\H is negative becuase the system has lost energy to surroundings
Example is the combustion of hydrocarbon fuels
Endothermic
Decreases the temperature of surroundings
Increases the enthalpy of chemical systems as /\H is positive because the system has gained energy from surroundings
Example is the decomposition of metal carbonates e.g. CaCO3
Enthalpy Profile Diagrams
Enthalpy Profile Diagrams
Chemical reaction can be regarded as braking bonds followed by making bonds. Braking bonds needs energy, so energy must be put into the reaction
The minimum energy needed to start a reaction is called activation energy
After that bonds a re made which release energy
When bonds are broken energy is taken in positive
When bonds are made, energy is released, negative
If the bonds made are stronger than the bonds broken then there is a overall decrease in enthalpy and the reaction is exothermic
If the bonds broken are stronger than the bonds made there is an overall increase in enthalpy and the reaction in endothermic
Types of Enthalpy Change
r=change of reaction
c=chanhe of combustion
f=change of formation
Standard Enthalpy change of formation definition
Enthalpy change when 1 mole of a compound is formed from its constituent elements in their standard states under standard conditions.
When standard state=0
Standard enthalpy change of combustion
Enthalpy change when 1 mole of a substance (element or compound) reacts completely with oxygen under standard conditions
Standard enthalpy change of reaction
The enthalpy change that accompanies a reaction under standard conditions in the molar quantities expressed in a chemical equation, all reactants and products being in their standard states
How to calculate enthalpy changes
Energy change in surroundings = m x c x T(difference in Temperature)
m=mass
c=4.2 (A constatnt)
50cm^3 of concentrated sulfuric acid 20.0mol dm^-3, was added to 950cm^3 of water at a temperature of 19Celcius. The solutionwas stirred gently until maximum temperature was reached at 28C. What is the enthalpy change for this reaction?
STEP 1 : Write the equation. m x c x T=energy change
STEP 2 : Write down values for symbols m, c and T. m=950+50=1000cm^3 c=4.2J T=28-19=9C
STEP 3 : Do the calculation energy change = 1000 x 2.4 x 9= 37000J=37.8kJ
It is an exothermic reaction so it has a negative sign -37.8kJ
What is the enthalpy change per mole of sulfuric acid?
STEP 4 : Calculate the amount in moles of Sulfuric acid
amount(mol)=Vol(cm^3)/1000 x concentration
50/1000 x 20 = 1.00 mol
STEP 5 : Divide the /\H value by moles =37.8/1 =37.8kJmol^-1
Hess's Law
Hess' Law states that for any chemical change the enthalpy change is the same whatever the route taken
/\H1=/\H2+/\H3
Calculating enthalpy changes indirectly using hess's Law