Phys II Exam 2

• 1) how charged the object creating the field is
• 2) the distance of separation from the charged object

magnitude of the electric field is simply defined as the force per charge on the test charge (q)

• E = F/q; unit is Newton/Couloumb (N/C)
• 

• NOT; increasing the amount of charge on the test charge would increase the denominator of the equation;
• -According to Coulomb's law, more charge also means more electric force (F)
• -So any increase in q would be accompanied by an increase in F
• -As the denominator in the equation increases by a factor, the numerator increases by the SAME factor
• -The two changes offset each other

F = k * q * Q/R2

• -the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the distance between the two objects

point in the direction that a positive test charge would accelerate if placed upon the patterns of lines

• two charges are closest together
• -DECREASING the separation distance INCREASES the force
• -the magnitude of the force and the distance between the two balloons is inversely related